How to Solve Ant on the Boundary Problem
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Ant on the Boundary
An ant is on a boundary. It sometimes goes left and sometimes right. You are given an array of non-zero integers nums. The ant starts reading nums from the first element of it to its end. At each step...
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Understanding the Ant on the Boundary Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
An ant is on a boundary. It sometimes goes left and sometimes right. You are given an array of non-zero integers nums. The ant starts reading nums from the first element of it to its end. At each step, it moves according to the value of the current element: If nums[i] < 0, it moves left by -nums[i] units. If nums[i] > 0, it moves right by nums[i] units. Return the number of times the ant returns to the boundary. Notes: There is an infinite space on both sides of the boundary. We check whether the ant is on the boundary only after it has moved |nums[i]| units. In other words, if the ant crosses the boundary during its movement, it does not count.
Ant on the Boundary
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Examples
nums = [2,3,-5]1After the first step, the ant is 2 steps to the right of the boundary. After the second step, the ant is 5 steps to the right of the boundary. After the third step, the ant is on the boundary. So the answer is 1.
nums = [3,2,-3,-4]0After the first step, the ant is 3 steps to the right of the boundary. After the second step, the ant is 5 steps to the right of the boundary. After the third step, the ant is 2 steps to the right of the boundary. After the fourth step, the ant is 2 steps to the left of the boundary. The ant never returned to the boundary, so the answer is 0.
Constraints
1 <= nums.length <= 10010 <= nums[i] <= 10nums[i] != 0How Interview Coder Helps with Leetcode Problems
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