How to Solve Check if a Parentheses String Can Be Valid Problem
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Check if a Parentheses String Can Be Valid
A parentheses string is a non-empty string consisting only of '(' and ')'. It is valid if any of the following conditions is true: It is (). It can be written as AB (A concatenated with B), where A an...
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Understanding the Check if a Parentheses String Can Be Valid Problem
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Problem Statement
A parentheses string is a non-empty string consisting only of '(' and ')'. It is valid if any of the following conditions is true: It is (). It can be written as AB (A concatenated with B), where A and B are valid parentheses strings. It can be written as (A), where A is a valid parentheses string. You are given a parentheses string s and a string locked, both of length n. locked is a binary string consisting only of '0's and '1's. For each index i of locked, If locked[i] is '1', you cannot change s[i]. But if locked[i] is '0', you can change s[i] to either '(' or ')'. Return true if you can make s a valid parentheses string. Otherwise, return false.
Check if a Parentheses String Can Be Valid
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Examples
s = "))()))", locked = "010100"truelocked[1] == '1' and locked[3] == '1', so we cannot change s[1] or s[3]. We change s[0] and s[4] to '(' while leaving s[2] and s[5] unchanged to make s valid.
s = "()()", locked = "0000"trueWe do not need to make any changes because s is already valid.
s = ")", locked = "0"falselocked permits us to change s[0]. Changing s[0] to either '(' or ')' will not make s valid.
s = "(((())(((())", locked = "111111010111"truelocked permits us to change s[6] and s[8]. We change s[6] and s[8] to ')' to make s valid.
Constraints
n == s.length == locked.length1 <= n <= 105s[i] is either '(' or ')'.locked[i] is either '0' or '1'.How Interview Coder Helps with Leetcode Problems
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