How to Solve Count Good Nodes in Binary Tree Leetcode Problem - Interview Coder Guide
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How to Solve Count Good Nodes in Binary Tree Problem

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Medium#1544
LeetCode Problem

Count Good Nodes in Binary Tree

Given a binary tree root, a node X in the tree is named good if in the path from root to X there are no nodes with a value greater than X. Return the number of good nodes in the binary tree.

TreeDepth-First SearchBreadth-First Search+1 more

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Problem Breakdown

Understanding the Count Good Nodes in Binary Tree Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

Given a binary tree root, a node X in the tree is named good if in the path from root to X there are no nodes with a value greater than X. Return the number of good nodes in the binary tree.

MediumProblem #1544
LeetCode

Count Good Nodes in Binary Tree

Related Topics
TreeDepth-First SearchBreadth-First SearchBinary Tree
How Interview Coder Helps

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Examples

Example 1
INPUT
root = [3,1,4,3,null,1,5]
OUTPUT
4
EXPLANATION

Nodes in blue are good. Root Node (3) is always a good node. Node 4 -> (3,4) is the maximum value in the path starting from the root. Node 5 -> (3,4,5) is the maximum value in the path Node 3 -> (3,1,3) is the maximum value in the path.

Example 2
INPUT
root = [3,3,null,4,2]
OUTPUT
3
EXPLANATION

Node 2 -> (3, 3, 2) is not good, because "3" is higher than it.

Example 3
INPUT
root = [1]
OUTPUT
1
EXPLANATION

Root is considered as good.

Constraints

The number of nodes in the binary tree is in the range [1, 10^5].
Each node's value is between [-10^4, 10^4].

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