How to Solve Count Pairs Of Similar Strings Problem
Master the Count Pairs Of Similar Strings LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
Interview Coder generates complete solutions and debugging hints that you can use while explaining your approach, so you stay calm and in control.
Count Pairs Of Similar Strings
You are given a 0-indexed string array words. Two strings are similar if they consist of the same characters. For example, "abca" and "cba" are similar since both consist of characters 'a', 'b', and '...
Interview Coder will help you solve this problem in real-time during your interview
✨ Get instant solutions, explanations, and code generation
Understanding the Count Pairs Of Similar Strings Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given a 0-indexed string array words. Two strings are similar if they consist of the same characters. For example, "abca" and "cba" are similar since both consist of characters 'a', 'b', and 'c'. However, "abacba" and "bcfd" are not similar since they do not consist of the same characters. Return the number of pairs (i, j) such that 0 <= i < j <= word.length - 1 and the two strings words[i] and words[j] are similar.
Count Pairs Of Similar Strings
Related Topics
How Interview Coder Helps
Get real-time assistance for Count Pairs Of Similar Strings problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
words = ["aba","aabb","abcd","bac","aabc"]
2
There are 2 pairs that satisfy the conditions: - i = 0 and j = 1 : both words[0] and words[1] only consist of characters 'a' and 'b'. - i = 3 and j = 4 : both words[3] and words[4] only consist of characters 'a', 'b', and 'c'.
words = ["aabb","ab","ba"]
3
There are 3 pairs that satisfy the conditions: - i = 0 and j = 1 : both words[0] and words[1] only consist of characters 'a' and 'b'. - i = 0 and j = 2 : both words[0] and words[2] only consist of characters 'a' and 'b'. - i = 1 and j = 2 : both words[1] and words[2] only consist of characters 'a' and 'b'.
words = ["nba","cba","dba"]
0
Since there does not exist any pair that satisfies the conditions, we return 0.
Constraints
1 <= words.length <= 100
1 <= words[i].length <= 100
words[i] consist of only lowercase English letters.
How Interview Coder Helps with Leetcode Problems
Trust anchors reduce friction for conversion. Reinforce undetectability claims, platform compatibility, user counts, and the free trial to remove perceived risk.
See Interview Coder in Action
Watch how Interview Coder helps solve LeetCode problems during live interviews
Undetectability Checklist
Platform Compatibility
User results and traction
More than 87,000 developers use Interview Coder and early launch metrics showed rapid adoption. Social proof signals that this approach helps real candidates land offers across a range of companies.
Undetectability and technical details
Our native desktop architecture avoids common detection vectors used by browser extensions. We provide a clear checklist so you can run basic checks and confirm the app will be invisible during live interviews.
Platform compatibility and limitations
We work with Zoom, HackerRank, CodeSignal, CoderPad and other web based platforms, with a known list of app version caveats. Check the compatibility note and request a browser link if a specific desktop app is unsupported.
Frequently Asked Questions
Common questions about solving Count Pairs Of Similar Strings and using Interview Coder during coding interviews.
Interview Coder generates complete solutions instantly with proper complexity analysis, letting you focus on explaining your approach and demonstrating problem-solving skills rather than getting stuck on implementation details during high-pressure situations.
Ready to Get Started?
Download Interview Coder now and join thousands of developers who have aced their coding interviews