How to Solve Even Odd Tree Problem
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Even Odd Tree
A binary tree is named Even-Odd if it meets the following conditions: The root of the binary tree is at level index 0, its children are at level index 1, their children are at level index 2, etc. For ...
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Understanding the Even Odd Tree Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
A binary tree is named Even-Odd if it meets the following conditions: The root of the binary tree is at level index 0, its children are at level index 1, their children are at level index 2, etc. For every even-indexed level, all nodes at the level have odd integer values in strictly increasing order (from left to right). For every odd-indexed level, all nodes at the level have even integer values in strictly decreasing order (from left to right). Given the root of a binary tree, return true if the binary tree is Even-Odd, otherwise return false.
Even Odd Tree
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Examples
root = [1,10,4,3,null,7,9,12,8,6,null,null,2]
true
The node values on each level are: Level 0: [1] Level 1: [10,4] Level 2: [3,7,9] Level 3: [12,8,6,2] Since levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd.
root = [5,4,2,3,3,7]
false
The node values on each level are: Level 0: [5] Level 1: [4,2] Level 2: [3,3,7] Node values in level 2 must be in strictly increasing order, so the tree is not Even-Odd.
root = [5,9,1,3,5,7]
false
Node values in the level 1 should be even integers.
Constraints
The number of nodes in the tree is in the range [1, 105].
1 <= Node.val <= 106
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