How to Solve Find Building Where Alice and Bob Can Meet Problem
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Find Building Where Alice and Bob Can Meet
You are given a 0-indexed array heights of positive integers, where heights[i] represents the height of the ith building. If a person is in building i, they can move to any other building j if and onl...
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Understanding the Find Building Where Alice and Bob Can Meet Problem
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Problem Statement
You are given a 0-indexed array heights of positive integers, where heights[i] represents the height of the ith building. If a person is in building i, they can move to any other building j if and only if i < j and heights[i] < heights[j]. You are also given another array queries where queries[i] = [ai, bi]. On the ith query, Alice is in building ai while Bob is in building bi. Return an array ans where ans[i] is the index of the leftmost building where Alice and Bob can meet on the ith query. If Alice and Bob cannot move to a common building on query i, set ans[i] to -1.
Find Building Where Alice and Bob Can Meet
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Examples
heights = [6,4,8,5,2,7], queries = [[0,1],[0,3],[2,4],[3,4],[2,2]][2,5,-1,5,2]In the first query, Alice and Bob can move to building 2 since heights[0] < heights[2] and heights[1] < heights[2]. In the second query, Alice and Bob can move to building 5 since heights[0] < heights[5] and heights[3] < heights[5]. In the third query, Alice cannot meet Bob since Alice cannot move to any other building. In the fourth query, Alice and Bob can move to building 5 since heights[3] < heights[5] and heights[4] < heights[5]. In the fifth query, Alice and Bob are already in the same building. For ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet. For ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.
heights = [5,3,8,2,6,1,4,6], queries = [[0,7],[3,5],[5,2],[3,0],[1,6]][7,6,-1,4,6]In the first query, Alice can directly move to Bob's building since heights[0] < heights[7]. In the second query, Alice and Bob can move to building 6 since heights[3] < heights[6] and heights[5] < heights[6]. In the third query, Alice cannot meet Bob since Bob cannot move to any other building. In the fourth query, Alice and Bob can move to building 4 since heights[3] < heights[4] and heights[0] < heights[4]. In the fifth query, Alice can directly move to Bob's building since
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