How to Solve Find the Minimum Amount of Time to Brew Potions Problem
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Find the Minimum Amount of Time to Brew Potions
You are given two integer arrays, skill and mana, of length n and m, respectively. In a laboratory, n wizards must brew m potions in order. Each potion has a mana capacity mana[j] and must pass throug...
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Problem Statement
You are given two integer arrays, skill and mana, of length n and m, respectively. In a laboratory, n wizards must brew m potions in order. Each potion has a mana capacity mana[j] and must pass through all the wizards sequentially to be brewed properly. The time taken by the ith wizard on the jth potion is timeij = skill[i] * mana[j]. Since the brewing process is delicate, a potion must be passed to the next wizard immediately after the current wizard completes their work. This means the timing must be synchronized so that each wizard begins working on a potion exactly when it arrives. Return the minimum amount of time required for the potions to be brewed properly.
Find the Minimum Amount of Time to Brew Potions
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Examples
skill = [1,5,2,4], mana = [5,1,4,2]110Potion Number Start time Wizard 0 done by Wizard 1 done by Wizard 2 done by Wizard 3 done by 0 0 5 30 40 60 1 52 53 58 60 64 2 54 58 78 86 102 3 86 88 98 102 110 As an example for why wizard 0 cannot start working on the 1st potion before time t = 52, consider the case where the wizards started preparing the 1st potion at time t = 50. At time t = 58, wizard 2 is done with the 1st potion, but wizard 3 will still be working on the 0th potion till time t = 60.
skill = [1,1,1], mana = [1,1,1]5Preparation of the 0th potion begins at time t = 0, and is completed by time t = 3. Preparation of the 1st potion begins at time t = 1, and is completed by time t = 4. Preparation of the 2nd potion begins at time t = 2, and is completed by time t = 5.
skill = [1,2,3,4], mana = [1,2]21Constraints
n == skill.lengthm == mana.length1 <= n, m <= 50001 <= mana[i], skill[i] <= 5000How Interview Coder Helps with Leetcode Problems
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