How to Solve Greatest Common Divisor Traversal Leetcode Problem - Interview Coder Guide
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How to Solve Greatest Common Divisor Traversal Problem

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Hard#2827
LeetCode Problem

Greatest Common Divisor Traversal

You are given a 0-indexed integer array nums, and you are allowed to traverse between its indices. You can traverse between index i and index j, i != j, if and only if gcd(nums[i], nums[j]) > 1, where...

ArrayMathUnion Find+1 more

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Problem Breakdown

Understanding the Greatest Common Divisor Traversal Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given a 0-indexed integer array nums, and you are allowed to traverse between its indices. You can traverse between index i and index j, i != j, if and only if gcd(nums[i], nums[j]) > 1, where gcd is the greatest common divisor. Your task is to determine if for every pair of indices i and j in nums, where i < j, there exists a sequence of traversals that can take us from i to j. Return true if it is possible to traverse between all such pairs of indices, or false otherwise.

HardProblem #2827
LeetCode

Greatest Common Divisor Traversal

Related Topics
ArrayMathUnion FindNumber Theory
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Examples

Example 1
INPUT
nums = [2,3,6]
OUTPUT
true
EXPLANATION

In this example, there are 3 possible pairs of indices: (0, 1), (0, 2), and (1, 2). To go from index 0 to index 1, we can use the sequence of traversals 0 -> 2 -> 1, where we move from index 0 to index 2 because gcd(nums[0], nums[2]) = gcd(2, 6) = 2 > 1, and then move from index 2 to index 1 because gcd(nums[2], nums[1]) = gcd(6, 3) = 3 > 1. To go from index 0 to index 2, we can just go directly because gcd(nums[0], nums[2]) = gcd(2, 6) = 2 > 1. Likewise, to go from index 1 to index 2, we can just go directly because gcd(nums[1], nums[2]) = gcd(3, 6) = 3 > 1.

Example 2
INPUT
nums = [3,9,5]
OUTPUT
false
EXPLANATION

No sequence of traversals can take us from index 0 to index 2 in this example. So, we return false.

Example 3
INPUT
nums = [4,3,12,8]
OUTPUT
true
EXPLANATION

There are 6 possible pairs of indices to traverse between: (0, 1), (0, 2), (0, 3), (1, 2), (1, 3), and (2, 3). A valid sequence of traversals exists for each pair, so we return true.

Constraints

1 <= nums.length <= 105
1 <= nums[i] <= 105

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