How to Solve Handling Sum Queries After Update Problem
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Handling Sum Queries After Update
You are given two 0-indexed arrays nums1 and nums2 and a 2D array queries of queries. There are three types of queries: For a query of type 1, queries[i] = [1, l, r]. Flip the values from 0 to 1 and f...
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Understanding the Handling Sum Queries After Update Problem
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Problem Statement
You are given two 0-indexed arrays nums1 and nums2 and a 2D array queries of queries. There are three types of queries: For a query of type 1, queries[i] = [1, l, r]. Flip the values from 0 to 1 and from 1 to 0 in nums1 from index l to index r. Both l and r are 0-indexed. For a query of type 2, queries[i] = [2, p, 0]. For every index 0 <= i < n, set nums2[i] = nums2[i] + nums1[i] * p. For a query of type 3, queries[i] = [3, 0, 0]. Find the sum of the elements in nums2. Return an array containing all the answers to the third type queries.
Handling Sum Queries After Update
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Examples
nums1 = [1,0,1], nums2 = [0,0,0], queries = [[1,1,1],[2,1,0],[3,0,0]][3]After the first query nums1 becomes [1,1,1]. After the second query, nums2 becomes [1,1,1], so the answer to the third query is 3. Thus, [3] is returned.
nums1 = [1], nums2 = [5], queries = [[2,0,0],[3,0,0]][5]After the first query, nums2 remains [5], so the answer to the second query is 5. Thus, [5] is returned.
Constraints
1 <= nums1.length,nums2.length <= 105nums1.length = nums2.length1 <= queries.length <= 105queries[i].length = 30 <= l <= r <= nums1.length - 10 <= p <= 1060 <= nums1[i] <= 10 <= nums2[i] <= 109How Interview Coder Helps with Leetcode Problems
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