How to Solve K Radius Subarray Averages Problem
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K Radius Subarray Averages
You are given a 0-indexed array nums of n integers, and an integer k. The k-radius average for a subarray of nums centered at some index i with the radius k is the average of all elements in nums betw...
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Understanding the K Radius Subarray Averages Problem
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Problem Statement
You are given a 0-indexed array nums of n integers, and an integer k. The k-radius average for a subarray of nums centered at some index i with the radius k is the average of all elements in nums between the indices i - k and i + k (inclusive). If there are less than k elements before or after the index i, then the k-radius average is -1. Build and return an array avgs of length n where avgs[i] is the k-radius average for the subarray centered at index i. The average of x elements is the sum of the x elements divided by x, using integer division. The integer division truncates toward zero, which means losing its fractional part. For example, the average of four elements 2, 3, 1, and 5 is (2 + 3 + 1 + 5) / 4 = 11 / 4 = 2.75, which truncates to 2.
K Radius Subarray Averages
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Examples
nums = [7,4,3,9,1,8,5,2,6], k = 3[-1,-1,-1,5,4,4,-1,-1,-1]- avg[0], avg[1], and avg[2] are -1 because there are less than k elements before each index. - The sum of the subarray centered at index 3 with radius 3 is: 7 + 4 + 3 + 9 + 1 + 8 + 5 = 37. Using integer division, avg[3] = 37 / 7 = 5. - For the subarray centered at index 4, avg[4] = (4 + 3 + 9 + 1 + 8 + 5 + 2) / 7 = 4. - For the subarray centered at index 5, avg[5] = (3 + 9 + 1 + 8 + 5 + 2 + 6) / 7 = 4. - avg[6], avg[7], and avg[8] are -1 because there are less than k elements after each index.
nums = [100000], k = 0[100000]- The sum of the subarray centered at index 0 with radius 0 is: 100000. avg[0] = 100000 / 1 = 100000.
nums = [8], k = 100000[-1]- avg[0] is -1 because there are less than k elements before and after index 0.
Constraints
n == nums.length1 <= n <= 1050 <= nums[i], k <= 105How Interview Coder Helps with Leetcode Problems
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