How to Solve Linked List Cycle I I Problem
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Linked List Cycle II
Given the head of a linked list, return the node where the cycle begins. If there is no cycle, return null. There is a cycle in a linked list if there is some node in the list that can be reached agai...
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Understanding the Linked List Cycle I I Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
Given the head of a linked list, return the node where the cycle begins. If there is no cycle, return null. There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next pointer. Internally, pos is used to denote the index of the node that tail's next pointer is connected to (0-indexed). It is -1 if there is no cycle. Note that pos is not passed as a parameter. Do not modify the linked list.
Linked List Cycle II
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Get real-time assistance for Linked List Cycle II problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
head = [3,2,0,-4], pos = 1tail connects to node index 1There is a cycle in the linked list, where tail connects to the second node.
head = [1,2], pos = 0tail connects to node index 0There is a cycle in the linked list, where tail connects to the first node.
head = [1], pos = -1no cycleThere is no cycle in the linked list.
Constraints
The number of the nodes in the list is in the range [0, 104].105 <= Node.val <= 105pos is -1 or a valid index in the linked-list.Follow up: Can you solve it using O(1) (i.e. constant) memory?How Interview Coder Helps with Leetcode Problems
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