How to Solve Longest Alternating Subarray Problem
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Longest Alternating Subarray
You are given a 0-indexed integer array nums. A subarray s of length m is called alternating if: m is greater than 1. s1 = s0 + 1. The 0-indexed subarray s looks like [s0, s1, s0, s1,...,s(m-1) % 2]. ...
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Understanding the Longest Alternating Subarray Problem
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Problem Statement
You are given a 0-indexed integer array nums. A subarray s of length m is called alternating if: m is greater than 1. s1 = s0 + 1. The 0-indexed subarray s looks like [s0, s1, s0, s1,...,s(m-1) % 2]. In other words, s1 - s0 = 1, s2 - s1 = -1, s3 - s2 = 1, s4 - s3 = -1, and so on up to s[m - 1] - s[m - 2] = (-1)m. Return the maximum length of all alternating subarrays present in nums or -1 if no such subarray exists. A subarray is a contiguous non-empty sequence of elements within an array.
Longest Alternating Subarray
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Examples
nums = [2,3,4,3,4]4The alternating subarrays are [2, 3], [3,4], [3,4,3], and [3,4,3,4]. The longest of these is [3,4,3,4], which is of length 4.
nums = [4,5,6]2[4,5] and [5,6] are the only two alternating subarrays. They are both of length 2.
Constraints
2 <= nums.length <= 1001 <= nums[i] <= 104How Interview Coder Helps with Leetcode Problems
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