How to Solve Manhattan Distances of All Arrangements of Pieces Leetcode Problem - Interview Coder Guide
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How to Solve Manhattan Distances of All Arrangements of Pieces Problem

Master the Manhattan Distances of All Arrangements of Pieces LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.

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Hard#3739
LeetCode Problem

Manhattan Distances of All Arrangements of Pieces

You are given three integers m, n, and k. There is a rectangular grid of size m × n containing k identical pieces. Return the sum of Manhattan distances between every pair of pieces over all valid arr...

MathCombinatorics

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Problem Breakdown

Understanding the Manhattan Distances of All Arrangements of Pieces Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given three integers m, n, and k. There is a rectangular grid of size m × n containing k identical pieces. Return the sum of Manhattan distances between every pair of pieces over all valid arrangements of pieces. A valid arrangement is a placement of all k pieces on the grid with at most one piece per cell. Since the answer may be very large, return it modulo 109 + 7. The Manhattan Distance between two cells (xi, yi) and (xj, yj) is |xi - xj| + |yi - yj|.

HardProblem #3739
LeetCode

Manhattan Distances of All Arrangements of Pieces

Related Topics
MathCombinatorics
How Interview Coder Helps

Get real-time assistance for Manhattan Distances of All Arrangements of Pieces problems during coding interviews. Interview Coder provides instant solutions and explanations.

Examples

Example 1
INPUT
m = 2, n = 2, k = 2
OUTPUT
8
EXPLANATION

The valid arrangements of pieces on the board are: In the first 4 arrangements, the Manhattan distance between the two pieces is 1. In the last 2 arrangements, the Manhattan distance between the two pieces is 2. Thus, the total Manhattan distance across all valid arrangements is 1 + 1 + 1 + 1 + 2 + 2 = 8.

Example 2
INPUT
m = 1, n = 4, k = 3
OUTPUT
20
EXPLANATION

The valid arrangements of pieces on the board are: The first and last arrangements have a total Manhattan distance of 1 + 1 + 2 = 4. The middle two arrangements have a total Manhattan distance of 1 + 2 + 3 = 6. The total Manhattan distance between all pairs of pieces across all arrangements is 4 + 6 + 6 + 4 = 20.

Constraints

1 <= m, n <= 105
2 <= m * n <= 105
2 <= k <= m * n

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