How to Solve Maximize Subarray Sum After Removing All Occurrences of One Element Problem
Master the Maximize Subarray Sum After Removing All Occurrences of One Element LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
Interview Coder generates complete solutions and debugging hints that you can use while explaining your approach, so you stay calm and in control.
Maximize Subarray Sum After Removing All Occurrences of One Element
You are given an integer array nums. You can do the following operation on the array at most once: Choose any integer x such that nums remains non-empty on removing all occurrences of x. Remove all oc...
Interview Coder will help you solve this problem in real-time during your interview
✨ Get instant solutions, explanations, and code generation
Understanding the Maximize Subarray Sum After Removing All Occurrences of One Element Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given an integer array nums. You can do the following operation on the array at most once: Choose any integer x such that nums remains non-empty on removing all occurrences of x. Remove all occurrences of x from the array. Return the maximum subarray sum across all possible resulting arrays.
Maximize Subarray Sum After Removing All Occurrences of One Element
Related Topics
How Interview Coder Helps
Get real-time assistance for Maximize Subarray Sum After Removing All Occurrences of One Element problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
nums = [-3,2,-2,-1,3,-2,3]
7
We can have the following arrays after at most one operation: The original array is nums = [-3, 2, -2, -1, 3, -2, 3]. The maximum subarray sum is 3 + (-2) + 3 = 4. Deleting all occurences of x = -3 results in nums = [2, -2, -1, 3, -2, 3]. The maximum subarray sum is 3 + (-2) + 3 = 4. Deleting all occurences of x = -2 results in nums = [-3, 2, -1, 3, 3]. The maximum subarray sum is 2 + (-1) + 3 + 3 = 7. Deleting all occurences of x = -1 results in nums = [-3, 2, -2, 3, -2, 3]. The maximum subarray sum is 3 + (-2) + 3 = 4. Deleting all occurences of x = 3 results in nums = [-3, 2, -2, -1, -2]. The maximum subarray sum is 2. The output is max(4, 4, 7, 4, 2) = 7.
nums = [1,2,3,4]
10
It is optimal to not perform any operations.
Constraints
1 <= nums.length <= 105
106 <= nums[i] <= 106
How Interview Coder Helps with Leetcode Problems
Trust anchors reduce friction for conversion. Reinforce undetectability claims, platform compatibility, user counts, and the free trial to remove perceived risk.
See Interview Coder in Action
Watch how Interview Coder helps solve LeetCode problems during live interviews
Undetectability Checklist
Platform Compatibility
User results and traction
More than 87,000 developers use Interview Coder and early launch metrics showed rapid adoption. Social proof signals that this approach helps real candidates land offers across a range of companies.
Undetectability and technical details
Our native desktop architecture avoids common detection vectors used by browser extensions. We provide a clear checklist so you can run basic checks and confirm the app will be invisible during live interviews.
Platform compatibility and limitations
We work with Zoom, HackerRank, CodeSignal, CoderPad and other web based platforms, with a known list of app version caveats. Check the compatibility note and request a browser link if a specific desktop app is unsupported.
Frequently Asked Questions
Common questions about solving Maximize Subarray Sum After Removing All Occurrences of One Element and using Interview Coder during coding interviews.
Interview Coder generates complete solutions instantly with proper complexity analysis, letting you focus on explaining your approach and demonstrating problem-solving skills rather than getting stuck on implementation details during high-pressure situations.
Ready to Get Started?
Download Interview Coder now and join thousands of developers who have aced their coding interviews