How to Solve Maximize the Topmost Element After K Moves Leetcode Problem - Interview Coder Guide
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How to Solve Maximize the Topmost Element After K Moves Problem

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Medium#1346
LeetCode Problem

Maximize the Topmost Element After K Moves

You are given a 0-indexed integer array nums representing the contents of a pile, where nums[0] is the topmost element of the pile. In one move, you can perform either of the following: If the pile is...

ArrayGreedy

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Problem Breakdown

Understanding the Maximize the Topmost Element After K Moves Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given a 0-indexed integer array nums representing the contents of a pile, where nums[0] is the topmost element of the pile. In one move, you can perform either of the following: If the pile is not empty, remove the topmost element of the pile. If there are one or more removed elements, add any one of them back onto the pile. This element becomes the new topmost element. You are also given an integer k, which denotes the total number of moves to be made. Return the maximum value of the topmost element of the pile possible after exactly k moves. In case it is not possible to obtain a non-empty pile after k moves, return -1.

MediumProblem #1346
LeetCode

Maximize the Topmost Element After K Moves

Related Topics
ArrayGreedy
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Examples

Example 1
INPUT
nums = [5,2,2,4,0,6], k = 4
OUTPUT
5
EXPLANATION

One of the ways we can end with 5 at the top of the pile after 4 moves is as follows: - Step 1: Remove the topmost element = 5. The pile becomes [2,2,4,0,6]. - Step 2: Remove the topmost element = 2. The pile becomes [2,4,0,6]. - Step 3: Remove the topmost element = 2. The pile becomes [4,0,6]. - Step 4: Add 5 back onto the pile. The pile becomes [5,4,0,6]. Note that this is not the only way to end with 5 at the top of the pile. It can be shown that 5 is the largest answer possible after 4 moves.

Example 2
INPUT
nums = [2], k = 1
OUTPUT
-1
EXPLANATION

In the first move, our only option is to pop the topmost element of the pile. Since it is not possible to obtain a non-empty pile after one move, we return -1.

Constraints

1 <= nums.length <= 105
0 <= nums[i], k <= 109

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