How to Solve Maximum Alternating Subsequence Sum Problem
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Maximum Alternating Subsequence Sum
The alternating sum of a 0-indexed array is defined as the sum of the elements at even indices minus the sum of the elements at odd indices. For example, the alternating sum of [4,2,5,3] is (4 + 5) - ...
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Understanding the Maximum Alternating Subsequence Sum Problem
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Problem Statement
The alternating sum of a 0-indexed array is defined as the sum of the elements at even indices minus the sum of the elements at odd indices. For example, the alternating sum of [4,2,5,3] is (4 + 5) - (2 + 3) = 4. Given an array nums, return the maximum alternating sum of any subsequence of nums (after reindexing the elements of the subsequence). A subsequence of an array is a new array generated from the original array by deleting some elements (possibly none) without changing the remaining elements' relative order. For example, [2,7,4] is a subsequence of [4,2,3,7,2,1,4] (the underlined elements), while [2,4,2] is not.
Maximum Alternating Subsequence Sum
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Examples
nums = [4,2,5,3]
7
It is optimal to choose the subsequence [4,2,5] with alternating sum (4 + 5) - 2 = 7.
nums = [5,6,7,8]
8
It is optimal to choose the subsequence [8] with alternating sum 8.
nums = [6,2,1,2,4,5]
10
It is optimal to choose the subsequence [6,1,5] with alternating sum (6 + 5) - 1 = 10.
Constraints
1 <= nums.length <= 105
1 <= nums[i] <= 105
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