How to Solve Maximum Amount of Money Robot Can Earn Leetcode Problem - Interview Coder Guide
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How to Solve Maximum Amount of Money Robot Can Earn Problem

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Medium#3677
LeetCode Problem

Maximum Amount of Money Robot Can Earn

You are given an m x n grid. A robot starts at the top-left corner of the grid (0, 0) and wants to reach the bottom-right corner (m - 1, n - 1). The robot can move either right or down at any point in...

ArrayDynamic ProgrammingMatrix

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Problem Breakdown

Understanding the Maximum Amount of Money Robot Can Earn Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given an m x n grid. A robot starts at the top-left corner of the grid (0, 0) and wants to reach the bottom-right corner (m - 1, n - 1). The robot can move either right or down at any point in time. The grid contains a value coins[i][j] in each cell: If coins[i][j] >= 0, the robot gains that many coins. If coins[i][j] < 0, the robot encounters a robber, and the robber steals the absolute value of coins[i][j] coins. The robot has a special ability to neutralize robbers in at most 2 cells on its path, preventing them from stealing coins in those cells. Note: The robot's total coins can be negative. Return the maximum profit the robot can gain on the route.

MediumProblem #3677
LeetCode

Maximum Amount of Money Robot Can Earn

Related Topics
ArrayDynamic ProgrammingMatrix
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Examples

Example 1
INPUT
coins = [[0,1,-1],[1,-2,3],[2,-3,4]]
OUTPUT
8
EXPLANATION

An optimal path for maximum coins is: Start at (0, 0) with 0 coins (total coins = 0). Move to (0, 1), gaining 1 coin (total coins = 0 + 1 = 1). Move to (1, 1), where there's a robber stealing 2 coins. The robot uses one neutralization here, avoiding the robbery (total coins = 1). Move to (1, 2), gaining 3 coins (total coins = 1 + 3 = 4). Move to (2, 2), gaining 4 coins (total coins = 4 + 4 = 8).

Example 2
INPUT
coins = [[10,10,10],[10,10,10]]
OUTPUT
40
EXPLANATION

An optimal path for maximum coins is: Start at (0, 0) with 10 coins (total coins = 10). Move to (0, 1), gaining 10 coins (total coins = 10 + 10 = 20). Move to (0, 2), gaining another 10 coins (total coins = 20 + 10 = 30). Move to (1, 2), gaining the final 10 coins (total coins = 30 + 10 = 40).

Constraints

m == coins.length
n == coins[i].length
1 <= m, n <= 500
1000 <= coins[i][j] <= 1000

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