How to Solve Maximum Area of Longest Diagonal Rectangle Problem
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Maximum Area of Longest Diagonal Rectangle
You are given a 2D 0-indexed integer array dimensions. For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle ...
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Understanding the Maximum Area of Longest Diagonal Rectangle Problem
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Problem Statement
You are given a 2D 0-indexed integer array dimensions. For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle i. Return the area of the rectangle having the longest diagonal. If there are multiple rectangles with the longest diagonal, return the area of the rectangle having the maximum area.
Maximum Area of Longest Diagonal Rectangle
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Examples
dimensions = [[9,3],[8,6]]48For index = 0, length = 9 and width = 3. Diagonal length = sqrt(9 * 9 + 3 * 3) = sqrt(90) ≈ 9.487. For index = 1, length = 8 and width = 6. Diagonal length = sqrt(8 * 8 + 6 * 6) = sqrt(100) = 10. So, the rectangle at index 1 has a greater diagonal length therefore we return area = 8 * 6 = 48.
dimensions = [[3,4],[4,3]]12Length of diagonal is the same for both which is 5, so maximum area = 12.
Constraints
1 <= dimensions.length <= 100dimensions[i].length == 21 <= dimensions[i][0], dimensions[i][1] <= 100How Interview Coder Helps with Leetcode Problems
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