How to Solve Maximum Median Sum of Subsequences of Size 3 Leetcode Problem - Interview Coder Guide
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How to Solve Maximum Median Sum of Subsequences of Size 3 Problem

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Medium#3766
LeetCode Problem

Maximum Median Sum of Subsequences of Size 3

You are given an integer array nums with a length divisible by 3. You want to make the array empty in steps. In each step, you can select any three elements from the array, compute their median, and r...

ArrayMathGreedy+2 more

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Problem Breakdown

Understanding the Maximum Median Sum of Subsequences of Size 3 Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given an integer array nums with a length divisible by 3. You want to make the array empty in steps. In each step, you can select any three elements from the array, compute their median, and remove the selected elements from the array. The median of an odd-length sequence is defined as the middle element of the sequence when it is sorted in non-decreasing order. Return the maximum possible sum of the medians computed from the selected elements.

MediumProblem #3766
LeetCode

Maximum Median Sum of Subsequences of Size 3

Related Topics
ArrayMathGreedySortingGame Theory
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Examples

Example 1
INPUT
nums = [2,1,3,2,1,3]
OUTPUT
5
EXPLANATION

In the first step, select elements at indices 2, 4, and 5, which have a median 3. After removing these elements, nums becomes [2, 1, 2]. In the second step, select elements at indices 0, 1, and 2, which have a median 2. After removing these elements, nums becomes empty. Hence, the sum of the medians is 3 + 2 = 5.

Example 2
INPUT
nums = [1,1,10,10,10,10]
OUTPUT
20
EXPLANATION

In the first step, select elements at indices 0, 2, and 3, which have a median 10. After removing these elements, nums becomes [1, 10, 10]. In the second step, select elements at indices 0, 1, and 2, which have a median 10. After removing these elements, nums becomes empty. Hence, the sum of the medians is 10 + 10 = 20.

Constraints

1 <= nums.length <= 5 * 105
nums.length % 3 == 0
1 <= nums[i] <= 109

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