How to Solve Maximum Number of Jumps to Reach the Last Index Problem
Master the Maximum Number of Jumps to Reach the Last Index LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
Interview Coder generates complete solutions and debugging hints that you can use while explaining your approach, so you stay calm and in control.
Maximum Number of Jumps to Reach the Last Index
You are given a 0-indexed array nums of n integers and an integer target. You are initially positioned at index 0. In one step, you can jump from index i to any index j such that: 0 <= i < j < n -targ...
Interview Coder will help you solve this problem in real-time during your interview
✨ Get instant solutions, explanations, and code generation
Understanding the Maximum Number of Jumps to Reach the Last Index Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given a 0-indexed array nums of n integers and an integer target. You are initially positioned at index 0. In one step, you can jump from index i to any index j such that: 0 <= i < j < n -target <= nums[j] - nums[i] <= target Return the maximum number of jumps you can make to reach index n - 1. If there is no way to reach index n - 1, return -1.
Maximum Number of Jumps to Reach the Last Index
Related Topics
How Interview Coder Helps
Get real-time assistance for Maximum Number of Jumps to Reach the Last Index problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
nums = [1,3,6,4,1,2], target = 23To go from index 0 to index n - 1 with the maximum number of jumps, you can perform the following jumping sequence: - Jump from index 0 to index 1. - Jump from index 1 to index 3. - Jump from index 3 to index 5. It can be proven that there is no other jumping sequence that goes from 0 to n - 1 with more than 3 jumps. Hence, the answer is 3.
nums = [1,3,6,4,1,2], target = 35To go from index 0 to index n - 1 with the maximum number of jumps, you can perform the following jumping sequence: - Jump from index 0 to index 1. - Jump from index 1 to index 2. - Jump from index 2 to index 3. - Jump from index 3 to index 4. - Jump from index 4 to index 5. It can be proven that there is no other jumping sequence that goes from 0 to n - 1 with more than 5 jumps. Hence, the answer is 5.
nums = [1,3,6,4,1,2], target = 0-1It can be proven that there is no jumping sequence that goes from 0 to n - 1. Hence, the answer is -1.
Constraints
2 <= nums.length == n <= 1000109 <= nums[i] <= 1090 <= target <= 2 * 109How Interview Coder Helps with Leetcode Problems
Trust anchors reduce friction for conversion. Reinforce undetectability claims, platform compatibility, user counts, and the free trial to remove perceived risk.
See Interview Coder in Action
Watch how Interview Coder helps solve LeetCode problems during live interviews
Undetectability Checklist
Platform Compatibility
User results and traction
More than 87,000 developers use Interview Coder and early launch metrics showed rapid adoption. Social proof signals that this approach helps real candidates land offers across a range of companies.
Undetectability and technical details
Our native desktop architecture avoids common detection vectors used by browser extensions. We provide a clear checklist so you can run basic checks and confirm the app will be invisible during live interviews.
Platform compatibility and limitations
We work with Zoom, HackerRank, CodeSignal, CoderPad and other web based platforms, with a known list of app version caveats. Check the compatibility note and request a browser link if a specific desktop app is unsupported.
Frequently Asked Questions
Common questions about solving Maximum Number of Jumps to Reach the Last Index and using Interview Coder during coding interviews.
Interview Coder generates complete solutions instantly with proper complexity analysis, letting you focus on explaining your approach and demonstrating problem-solving skills rather than getting stuck on implementation details during high-pressure situations.
Ready to Get Started?
Download Interview Coder now and join thousands of developers who have aced their coding interviews