How to Solve Maximum Performance of a Team Leetcode Problem - Interview Coder Guide
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How to Solve Maximum Performance of a Team Problem

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Hard#1499
LeetCode Problem

Maximum Performance of a Team

You are given two integers n and k and two integer arrays speed and efficiency both of length n. There are n engineers numbered from 1 to n. speed[i] and efficiency[i] represent the speed and efficien...

ArrayGreedySorting+1 more

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Problem Breakdown

Understanding the Maximum Performance of a Team Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given two integers n and k and two integer arrays speed and efficiency both of length n. There are n engineers numbered from 1 to n. speed[i] and efficiency[i] represent the speed and efficiency of the ith engineer respectively. Choose at most k different engineers out of the n engineers to form a team with the maximum performance. The performance of a team is the sum of its engineers' speeds multiplied by the minimum efficiency among its engineers. Return the maximum performance of this team. Since the answer can be a huge number, return it modulo 109 + 7.

HardProblem #1499
LeetCode

Maximum Performance of a Team

Related Topics
ArrayGreedySortingHeap (Priority Queue)
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Examples

Example 1
INPUT
n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2
OUTPUT
60
EXPLANATION

We have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) * min(4, 7) = 60.

Example 2
INPUT
n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3
OUTPUT
68
EXPLANATION

This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) * min(5, 4, 7) = 68.

Example 3
INPUT
n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4
OUTPUT
72

Constraints

1 <= k <= n <= 105
speed.length == n
efficiency.length == n
1 <= speed[i] <= 105
1 <= efficiency[i] <= 108

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