How to Solve Min Max Game Problem
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Min Max Game
You are given a 0-indexed integer array nums whose length is a power of 2. Apply the following algorithm on nums: Let n be the length of nums. If n == 1, end the process. Otherwise, create a new 0-ind...
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Understanding the Min Max Game Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given a 0-indexed integer array nums whose length is a power of 2. Apply the following algorithm on nums: Let n be the length of nums. If n == 1, end the process. Otherwise, create a new 0-indexed integer array newNums of length n / 2. For every even index i where 0 <= i < n / 2, assign the value of newNums[i] as min(nums[2 * i], nums[2 * i + 1]). For every odd index i where 0 <= i < n / 2, assign the value of newNums[i] as max(nums[2 * i], nums[2 * i + 1]). Replace the array nums with newNums. Repeat the entire process starting from step 1. Return the last number that remains in nums after applying the algorithm.
Min Max Game
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Get real-time assistance for Min Max Game problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
nums = [1,3,5,2,4,8,2,2]1The following arrays are the results of applying the algorithm repeatedly. First: nums = [1,5,4,2] Second: nums = [1,4] Third: nums = [1] 1 is the last remaining number, so we return 1.
nums = [3]33 is already the last remaining number, so we return 3.
Constraints
1 <= nums.length <= 10241 <= nums[i] <= 109nums.length is a power of 2.How Interview Coder Helps with Leetcode Problems
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