How to Solve Minimum Absolute Sum Difference Problem
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Minimum Absolute Sum Difference
You are given two positive integer arrays nums1 and nums2, both of length n. The absolute sum difference of arrays nums1 and nums2 is defined as the sum of |nums1[i] - nums2[i]| for each 0 <= i < n (0...
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Understanding the Minimum Absolute Sum Difference Problem
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Problem Statement
You are given two positive integer arrays nums1 and nums2, both of length n. The absolute sum difference of arrays nums1 and nums2 is defined as the sum of |nums1[i] - nums2[i]| for each 0 <= i < n (0-indexed). You can replace at most one element of nums1 with any other element in nums1 to minimize the absolute sum difference. Return the minimum absolute sum difference after replacing at most one element in the array nums1. Since the answer may be large, return it modulo 109 + 7. |x| is defined as: x if x >= 0, or -x if x < 0.
Minimum Absolute Sum Difference
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Examples
nums1 = [1,7,5], nums2 = [2,3,5]3There are two possible optimal solutions: - Replace the second element with the first: [1,7,5] => [1,1,5], or - Replace the second element with the third: [1,7,5] => [1,5,5]. Both will yield an absolute sum difference of |1-2| + (|1-3| or |5-3|) + |5-5| = 3.
nums1 = [2,4,6,8,10], nums2 = [2,4,6,8,10]0nums1 is equal to nums2 so no replacement is needed. This will result in an absolute sum difference of 0.
nums1 = [1,10,4,4,2,7], nums2 = [9,3,5,1,7,4]20Replace the first element with the second: [1,10,4,4,2,7] => [10,10,4,4,2,7]. This yields an absolute sum difference of |10-9| + |10-3| + |4-5| + |4-1| + |2-7| + |7-4| = 20
Constraints
n == nums1.lengthn == nums2.length1 <= n <= 1051 <= nums1[i], nums2[i] <= 105How Interview Coder Helps with Leetcode Problems
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