How to Solve Minimum Cost Path with Alternating Directions I I Problem
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Minimum Cost Path with Alternating Directions II
You are given two integers m and n representing the number of rows and columns of a grid, respectively. The cost to enter cell (i, j) is defined as (i + 1) * (j + 1). You are also given a 2D integer a...
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Understanding the Minimum Cost Path with Alternating Directions I I Problem
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Problem Statement
You are given two integers m and n representing the number of rows and columns of a grid, respectively. The cost to enter cell (i, j) is defined as (i + 1) * (j + 1). You are also given a 2D integer array waitCost where waitCost[i][j] defines the cost to wait on that cell. The path will always begin by entering cell (0, 0) on move 1 and paying the entrance cost. At each step, you follow an alternating pattern: On odd-numbered seconds, you must move right or down to an adjacent cell, paying its entry cost. On even-numbered seconds, you must wait in place for exactly one second and pay waitCost[i][j] during that second. Return the minimum total cost required to reach (m - 1, n - 1).
Minimum Cost Path with Alternating Directions II
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Examples
m = 1, n = 2, waitCost = [[1,2]]3The optimal path is: Start at cell (0, 0) at second 1 with entry cost (0 + 1) * (0 + 1) = 1. Second 1: Move right to cell (0, 1) with entry cost (0 + 1) * (1 + 1) = 2. Thus, the total cost is 1 + 2 = 3.
m = 2, n = 2, waitCost = [[3,5],[2,4]]9The optimal path is: Start at cell (0, 0) at second 1 with entry cost (0 + 1) * (0 + 1) = 1. Second 1: Move down to cell (1, 0) with entry cost (1 + 1) * (0 + 1) = 2. Second 2: Wait at cell (1, 0), paying waitCost[1][0] = 2. Second 3: Move right to cell (1, 1) with entry cost (1 + 1) * (1 + 1) = 4. Thus, the total cost is 1 + 2 + 2 + 4 = 9.
m = 2, n = 3, waitCost = [[6,1,4],[3,2,5]]16The optimal path is: Start at cell (0, 0) at second 1 with entry cost (0 + 1) * (0 + 1) = 1. Second 1: Move right to cell (0, 1) with entry cost (0 + 1) * (1 + 1) = 2. Second 2: Wait at cell (0, 1), paying waitCost[0][1] = 1. Second 3: Move down to cell (1, 1) with entry cost (1 + 1) * (1 + 1) = 4. Second 4: Wait at cell (1, 1), paying waitCost[1][1] = 2. Second 5: Move right to cell (1, 2) with entry cost (1 + 1) * (2 + 1) = 6. Thus, the total cost is 1 + 2 + 1 + 4 + 2 + 6 = 16.
Constraints
1 <= m, n <= 1052 <= m * nHow Interview Coder Helps with Leetcode Problems
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