How to Solve Minimum Cost to Make at Least One Valid Path in a Grid Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Cost to Make at Least One Valid Path in a Grid Problem

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Hard#1485
LeetCode Problem

Minimum Cost to Make at Least One Valid Path in a Grid

Given an m x n grid. Each cell of the grid has a sign pointing to the next cell you should visit if you are currently in this cell. The sign of grid[i][j] can be: 1 which means go to the cell to the r...

ArrayBreadth-First SearchGraph+3 more

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Problem Breakdown

Understanding the Minimum Cost to Make at Least One Valid Path in a Grid Problem

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Problem Statement

Given an m x n grid. Each cell of the grid has a sign pointing to the next cell you should visit if you are currently in this cell. The sign of grid[i][j] can be: 1 which means go to the cell to the right. (i.e go from grid[i][j] to grid[i][j + 1]) 2 which means go to the cell to the left. (i.e go from grid[i][j] to grid[i][j - 1]) 3 which means go to the lower cell. (i.e go from grid[i][j] to grid[i + 1][j]) 4 which means go to the upper cell. (i.e go from grid[i][j] to grid[i - 1][j]) Notice that there could be some signs on the cells of the grid that point outside the grid. You will initially start at the upper left cell (0, 0). A valid path in the grid is a path that starts from the upper left cell (0, 0) and ends at the bottom-right cell (m - 1, n - 1) following the signs on the grid. The valid path does not have to be the shortest. You can modify the sign on a cell with cost = 1. You can modify the sign on a cell one time only. Return the minimum cost to make the grid have at least one valid path.

HardProblem #1485
LeetCode

Minimum Cost to Make at Least One Valid Path in a Grid

Related Topics
ArrayBreadth-First SearchGraphHeap (Priority Queue)MatrixShortest Path
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Examples

Example 1
INPUT
grid = [[1,1,1,1],[2,2,2,2],[1,1,1,1],[2,2,2,2]]
OUTPUT
3
EXPLANATION

You will start at point (0, 0). The path to (3, 3) is as follows. (0, 0) --> (0, 1) --> (0, 2) --> (0, 3) change the arrow to down with cost = 1 --> (1, 3) --> (1, 2) --> (1, 1) --> (1, 0) change the arrow to down with cost = 1 --> (2, 0) --> (2, 1) --> (2, 2) --> (2, 3) change the arrow to down with cost = 1 --> (3, 3) The total cost = 3.

Example 2
INPUT
grid = [[1,1,3],[3,2,2],[1,1,4]]
OUTPUT
0
EXPLANATION

You can follow the path from (0, 0) to (2, 2).

Example 3
INPUT
grid = [[1,2],[4,3]]
OUTPUT
1

Constraints

m == grid.length
n == grid[i].length
1 <= m, n <= 100
1 <= grid[i][j] <= 4

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