How to Solve Minimum Deletions to Make String K- Special Problem
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Minimum Deletions to Make String K-Special
You are given a string word and an integer k. We consider word to be k-special if |freq(word[i]) - freq(word[j])| <= k for all indices i and j in the string. Here, freq(x) denotes the frequency of the...
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Understanding the Minimum Deletions to Make String K- Special Problem
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Problem Statement
You are given a string word and an integer k. We consider word to be k-special if |freq(word[i]) - freq(word[j])| <= k for all indices i and j in the string. Here, freq(x) denotes the frequency of the character x in word, and |y| denotes the absolute value of y. Return the minimum number of characters you need to delete to make word k-special.
Minimum Deletions to Make String K-Special
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Examples
word = "aabcaba", k = 0
3
We can make word 0-special by deleting 2 occurrences of "a" and 1 occurrence of "c". Therefore, word becomes equal to "baba" where freq('a') == freq('b') == 2.
word = "dabdcbdcdcd", k = 2
2
We can make word 2-special by deleting 1 occurrence of "a" and 1 occurrence of "d". Therefore, word becomes equal to "bdcbdcdcd" where freq('b') == 2, freq('c') == 3, and freq('d') == 4.
word = "aaabaaa", k = 2
1
We can make word 2-special by deleting 1 occurrence of "b". Therefore, word becomes equal to "aaaaaa" where each letter's frequency is now uniformly 6.
Constraints
1 <= word.length <= 105
0 <= k <= 105
word consists only of lowercase English letters.
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