How to Solve Minimum Difference in Sums After Removal of Elements Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Difference in Sums After Removal of Elements Problem

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Hard#2267
LeetCode Problem

Minimum Difference in Sums After Removal of Elements

You are given a 0-indexed integer array nums consisting of 3 * n elements. You are allowed to remove any subsequence of elements of size exactly n from nums. The remaining 2 * n elements will be divid...

ArrayDynamic ProgrammingHeap (Priority Queue)

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Problem Breakdown

Understanding the Minimum Difference in Sums After Removal of Elements Problem

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Problem Statement

You are given a 0-indexed integer array nums consisting of 3 * n elements. You are allowed to remove any subsequence of elements of size exactly n from nums. The remaining 2 * n elements will be divided into two equal parts: The first n elements belonging to the first part and their sum is sumfirst. The next n elements belonging to the second part and their sum is sumsecond. The difference in sums of the two parts is denoted as sumfirst - sumsecond. For example, if sumfirst = 3 and sumsecond = 2, their difference is 1. Similarly, if sumfirst = 2 and sumsecond = 3, their difference is -1. Return the minimum difference possible between the sums of the two parts after the removal of n elements.

HardProblem #2267
LeetCode

Minimum Difference in Sums After Removal of Elements

Related Topics
ArrayDynamic ProgrammingHeap (Priority Queue)
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Examples

Example 1
INPUT
nums = [3,1,2]
OUTPUT
-1
EXPLANATION

Here, nums has 3 elements, so n = 1. Thus we have to remove 1 element from nums and divide the array into two equal parts. - If we remove nums[0] = 3, the array will be [1,2]. The difference in sums of the two parts will be 1 - 2 = -1. - If we remove nums[1] = 1, the array will be [3,2]. The difference in sums of the two parts will be 3 - 2 = 1. - If we remove nums[2] = 2, the array will be [3,1]. The difference in sums of the two parts will be 3 - 1 = 2. The minimum difference between sums of the two parts is min(-1,1,2) = -1.

Example 2
INPUT
nums = [7,9,5,8,1,3]
OUTPUT
1
EXPLANATION

Here n = 2. So we must remove 2 elements and divide the remaining array into two parts containing two elements each. If we remove nums[2] = 5 and nums[3] = 8, the resultant array will be [7,9,1,3]. The difference in sums will be (7+9) - (1+3) = 12. To obtain the minimum difference, we should remove nums[1] = 9 and nums[4] = 1. The resultant array becomes [7,5,8,3]. The difference in sums of the two parts is (7+5) - (8+3) = 1. It can be shown that it is not possible to obtain a difference smaller than 1.

Constraints

nums.length == 3 * n
1 <= n <= 105
1 <= nums[i] <= 105

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