How to Solve Minimum Difficulty of a Job Schedule Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Difficulty of a Job Schedule Problem

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Hard#1457
LeetCode Problem

Minimum Difficulty of a Job Schedule

You want to schedule a list of jobs in d days. Jobs are dependent (i.e To work on the ith job, you have to finish all the jobs j where 0 <= j < i). You have to finish at least one task every day. The ...

ArrayDynamic Programming

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Problem Breakdown

Understanding the Minimum Difficulty of a Job Schedule Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You want to schedule a list of jobs in d days. Jobs are dependent (i.e To work on the ith job, you have to finish all the jobs j where 0 <= j < i). You have to finish at least one task every day. The difficulty of a job schedule is the sum of difficulties of each day of the d days. The difficulty of a day is the maximum difficulty of a job done on that day. You are given an integer array jobDifficulty and an integer d. The difficulty of the ith job is jobDifficulty[i]. Return the minimum difficulty of a job schedule. If you cannot find a schedule for the jobs return -1.

HardProblem #1457
LeetCode

Minimum Difficulty of a Job Schedule

Related Topics
ArrayDynamic Programming
How Interview Coder Helps

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Examples

Example 1
INPUT
jobDifficulty = [6,5,4,3,2,1], d = 2
OUTPUT
7
EXPLANATION

First day you can finish the first 5 jobs, total difficulty = 6. Second day you can finish the last job, total difficulty = 1. The difficulty of the schedule = 6 + 1 = 7

Example 2
INPUT
jobDifficulty = [9,9,9], d = 4
OUTPUT
-1
EXPLANATION

If you finish a job per day you will still have a free day. you cannot find a schedule for the given jobs.

Example 3
INPUT
jobDifficulty = [1,1,1], d = 3
OUTPUT
3
EXPLANATION

The schedule is one job per day. total difficulty will be 3.

Constraints

1 <= jobDifficulty.length <= 300
0 <= jobDifficulty[i] <= 1000
1 <= d <= 10

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