How to Solve Minimum Limit of Balls in a Bag Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Limit of Balls in a Bag Problem

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Medium#1886
LeetCode Problem

Minimum Limit of Balls in a Bag

You are given an integer array nums where the ith bag contains nums[i] balls. You are also given an integer maxOperations. You can perform the following operation at most maxOperations times: Take any...

ArrayBinary Search

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Problem Breakdown

Understanding the Minimum Limit of Balls in a Bag Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given an integer array nums where the ith bag contains nums[i] balls. You are also given an integer maxOperations. You can perform the following operation at most maxOperations times: Take any bag of balls and divide it into two new bags with a positive number of balls. For example, a bag of 5 balls can become two new bags of 1 and 4 balls, or two new bags of 2 and 3 balls. Your penalty is the maximum number of balls in a bag. You want to minimize your penalty after the operations. Return the minimum possible penalty after performing the operations.

MediumProblem #1886
LeetCode

Minimum Limit of Balls in a Bag

Related Topics
ArrayBinary Search
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Examples

Example 1
INPUT
nums = [9], maxOperations = 2
OUTPUT
3
EXPLANATION

- Divide the bag with 9 balls into two bags of sizes 6 and 3. [9] -> [6,3]. - Divide the bag with 6 balls into two bags of sizes 3 and 3. [6,3] -> [3,3,3]. The bag with the most number of balls has 3 balls, so your penalty is 3 and you should return 3.

Example 2
INPUT
nums = [2,4,8,2], maxOperations = 4
OUTPUT
2
EXPLANATION

- Divide the bag with 8 balls into two bags of sizes 4 and 4. [2,4,8,2] -> [2,4,4,4,2]. - Divide the bag with 4 balls into two bags of sizes 2 and 2. [2,4,4,4,2] -> [2,2,2,4,4,2]. - Divide the bag with 4 balls into two bags of sizes 2 and 2. [2,2,2,4,4,2] -> [2,2,2,2,2,4,2]. - Divide the bag with 4 balls into two bags of sizes 2 and 2. [2,2,2,2,2,4,2] -> [2,2,2,2,2,2,2,2]. The bag with the most number of balls has 2 balls, so your penalty is 2, and you should return 2.

Constraints

1 <= nums.length <= 105
1 <= maxOperations, nums[i] <= 109

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