How to Solve Minimum Number of Operations to Convert Time Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Number of Operations to Convert Time Problem

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Easy#2345
LeetCode Problem

Minimum Number of Operations to Convert Time

You are given two strings current and correct representing two 24-hour times. 24-hour times are formatted as "HH:MM", where HH is between 00 and 23, and MM is between 00 and 59. The earliest 24-hour t...

StringGreedy

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Problem Breakdown

Understanding the Minimum Number of Operations to Convert Time Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given two strings current and correct representing two 24-hour times. 24-hour times are formatted as "HH:MM", where HH is between 00 and 23, and MM is between 00 and 59. The earliest 24-hour time is 00:00, and the latest is 23:59. In one operation you can increase the time current by 1, 5, 15, or 60 minutes. You can perform this operation any number of times. Return the minimum number of operations needed to convert current to correct.

EasyProblem #2345
LeetCode

Minimum Number of Operations to Convert Time

Related Topics
StringGreedy
How Interview Coder Helps

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Examples

Example 1
INPUT
current = "02:30", correct = "04:35"
OUTPUT
3
EXPLANATION

We can convert current to correct in 3 operations as follows: - Add 60 minutes to current. current becomes "03:30". - Add 60 minutes to current. current becomes "04:30". - Add 5 minutes to current. current becomes "04:35". It can be proven that it is not possible to convert current to correct in fewer than 3 operations.

Example 2
INPUT
current = "11:00", correct = "11:01"
OUTPUT
1
EXPLANATION

We only have to add one minute to current, so the minimum number of operations needed is 1.

Constraints

current and correct are in the format "HH:MM"
current <= correct

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