How to Solve Minimum Operations to Exceed Threshold Value I I Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Operations to Exceed Threshold Value I I Problem

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Medium#3332
LeetCode Problem

Minimum Operations to Exceed Threshold Value II

You are given a 0-indexed integer array nums, and an integer k. You are allowed to perform some operations on nums, where in a single operation, you can: Select the two smallest integers x and y from ...

ArrayHeap (Priority Queue)Simulation

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Problem Breakdown

Understanding the Minimum Operations to Exceed Threshold Value I I Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given a 0-indexed integer array nums, and an integer k. You are allowed to perform some operations on nums, where in a single operation, you can: Select the two smallest integers x and y from nums. Remove x and y from nums. Insert (min(x, y) * 2 + max(x, y)) at any position in the array. Note that you can only apply the described operation if nums contains at least two elements. Return the minimum number of operations needed so that all elements of the array are greater than or equal to k.

MediumProblem #3332
LeetCode

Minimum Operations to Exceed Threshold Value II

Related Topics
ArrayHeap (Priority Queue)Simulation
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Examples

Example 1
INPUT
nums = [2,11,10,1,3], k = 10
OUTPUT
2
EXPLANATION

In the first operation, we remove elements 1 and 2, then add 1 * 2 + 2 to nums. nums becomes equal to [4, 11, 10, 3]. In the second operation, we remove elements 3 and 4, then add 3 * 2 + 4 to nums. nums becomes equal to [10, 11, 10]. At this stage, all the elements of nums are greater than or equal to 10 so we can stop. It can be shown that 2 is the minimum number of operations needed so that all elements of the array are greater than or equal to 10.

Example 2
INPUT
nums = [1,1,2,4,9], k = 20
OUTPUT
4
EXPLANATION

After one operation, nums becomes equal to [2, 4, 9, 3]. After two operations, nums becomes equal to [7, 4, 9]. After three operations, nums becomes equal to [15, 9]. After four operations, nums becomes equal to [33]. At this stage, all the elements of nums are greater than 20 so we can stop. It can be shown that 4 is the minimum number of operations needed so that all elements of the array are greater than or equal to 20.

Constraints

2 <= nums.length <= 2 * 105
1 <= nums[i] <= 109
1 <= k <= 109
The input is generated such that an answer always exists. That is, after performing some number of operations, all elements of the array are greater than or equal to k.

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