How to Solve Minimum Processing Time Leetcode Problem - Interview Coder Guide
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How to Solve Minimum Processing Time Problem

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Medium#3151
LeetCode Problem

Minimum Processing Time

You have a certain number of processors, each having 4 cores. The number of tasks to be executed is four times the number of processors. Each task must be assigned to a unique core, and each core can ...

ArrayGreedySorting

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Problem Breakdown

Understanding the Minimum Processing Time Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You have a certain number of processors, each having 4 cores. The number of tasks to be executed is four times the number of processors. Each task must be assigned to a unique core, and each core can only be used once. You are given an array processorTime representing the time each processor becomes available and an array tasks representing how long each task takes to complete. Return the minimum time needed to complete all tasks.

MediumProblem #3151
LeetCode

Minimum Processing Time

Related Topics
ArrayGreedySorting
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Examples

Example 1
INPUT
processorTime = [8,10], tasks = [2,2,3,1,8,7,4,5]
OUTPUT
16
EXPLANATION

Assign the tasks at indices 4, 5, 6, 7 to the first processor which becomes available at time = 8, and the tasks at indices 0, 1, 2, 3 to the second processor which becomes available at time = 10. The time taken by the first processor to finish the execution of all tasks is max(8 + 8, 8 + 7, 8 + 4, 8 + 5) = 16. The time taken by the second processor to finish the execution of all tasks is max(10 + 2, 10 + 2, 10 + 3, 10 + 1) = 13.

Example 2
INPUT
processorTime = [10,20], tasks = [2,3,1,2,5,8,4,3]
OUTPUT
23
EXPLANATION

Assign the tasks at indices 1, 4, 5, 6 to the first processor and the others to the second processor. The time taken by the first processor to finish the execution of all tasks is max(10 + 3, 10 + 5, 10 + 8, 10 + 4) = 18. The time taken by the second processor to finish the execution of all tasks is max(20 + 2, 20 + 1, 20 + 2, 20 + 3) = 23.

Constraints

1 <= n == processorTime.length <= 25000
1 <= tasks.length <= 105
0 <= processorTime[i] <= 109
1 <= tasks[i] <= 109
tasks.length == 4 * n

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