How to Solve Minimum Suffix Flips Problem
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Minimum Suffix Flips
You are given a 0-indexed binary string target of length n. You have another binary string s of length n that is initially set to all zeros. You want to make s equal to target. In one operation, you c...
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Understanding the Minimum Suffix Flips Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given a 0-indexed binary string target of length n. You have another binary string s of length n that is initially set to all zeros. You want to make s equal to target. In one operation, you can pick an index i where 0 <= i < n and flip all bits in the inclusive range [i, n - 1]. Flip means changing '0' to '1' and '1' to '0'. Return the minimum number of operations needed to make s equal to target.
Minimum Suffix Flips
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Examples
target = "10111"3Initially, s = "00000". Choose index i = 2: "00000" -> "00111" Choose index i = 0: "00111" -> "11000" Choose index i = 1: "11000" -> "10111" We need at least 3 flip operations to form target.
target = "101"3Initially, s = "000". Choose index i = 0: "000" -> "111" Choose index i = 1: "111" -> "100" Choose index i = 2: "100" -> "101" We need at least 3 flip operations to form target.
target = "00000"0We do not need any operations since the initial s already equals target.
Constraints
n == target.length1 <= n <= 105target[i] is either '0' or '1'.How Interview Coder Helps with Leetcode Problems
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