How to Solve Minimum Sum of Squared Difference Problem
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Minimum Sum of Squared Difference
You are given two positive 0-indexed integer arrays nums1 and nums2, both of length n. The sum of squared difference of arrays nums1 and nums2 is defined as the sum of (nums1[i] - nums2[i])2 for each ...
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Understanding the Minimum Sum of Squared Difference Problem
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Problem Statement
You are given two positive 0-indexed integer arrays nums1 and nums2, both of length n. The sum of squared difference of arrays nums1 and nums2 is defined as the sum of (nums1[i] - nums2[i])2 for each 0 <= i < n. You are also given two positive integers k1 and k2. You can modify any of the elements of nums1 by +1 or -1 at most k1 times. Similarly, you can modify any of the elements of nums2 by +1 or -1 at most k2 times. Return the minimum sum of squared difference after modifying array nums1 at most k1 times and modifying array nums2 at most k2 times. Note: You are allowed to modify the array elements to become negative integers.
Minimum Sum of Squared Difference
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Examples
nums1 = [1,2,3,4], nums2 = [2,10,20,19], k1 = 0, k2 = 0579The elements in nums1 and nums2 cannot be modified because k1 = 0 and k2 = 0. The sum of square difference will be: (1 - 2)2 + (2 - 10)2 + (3 - 20)2 + (4 - 19)2 = 579.
nums1 = [1,4,10,12], nums2 = [5,8,6,9], k1 = 1, k2 = 143One way to obtain the minimum sum of square difference is: - Increase nums1[0] once. - Increase nums2[2] once. The minimum of the sum of square difference will be: (2 - 5)2 + (4 - 8)2 + (10 - 7)2 + (12 - 9)2 = 43. Note that, there are other ways to obtain the minimum of the sum of square difference, but there is no way to obtain a sum smaller than 43.
Constraints
n == nums1.length == nums2.length1 <= n <= 1050 <= nums1[i], nums2[i] <= 1050 <= k1, k2 <= 109How Interview Coder Helps with Leetcode Problems
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