How to Solve Number of Subarrays That Match a Pattern I Leetcode Problem - Interview Coder Guide
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How to Solve Number of Subarrays That Match a Pattern I Problem

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Medium#3269
LeetCode Problem

Number of Subarrays That Match a Pattern I

You are given a 0-indexed integer array nums of size n, and a 0-indexed integer array pattern of size m consisting of integers -1, 0, and 1. A subarray nums[i..j] of size m + 1 is said to match the pa...

ArrayRolling HashString Matching+1 more

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Problem Breakdown

Understanding the Number of Subarrays That Match a Pattern I Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given a 0-indexed integer array nums of size n, and a 0-indexed integer array pattern of size m consisting of integers -1, 0, and 1. A subarray nums[i..j] of size m + 1 is said to match the pattern if the following conditions hold for each element pattern[k]: nums[i + k + 1] > nums[i + k] if pattern[k] == 1. nums[i + k + 1] == nums[i + k] if pattern[k] == 0. nums[i + k + 1] < nums[i + k] if pattern[k] == -1. Return the count of subarrays in nums that match the pattern.

MediumProblem #3269
LeetCode

Number of Subarrays That Match a Pattern I

Related Topics
ArrayRolling HashString MatchingHash Function
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Examples

Example 1
INPUT
nums = [1,2,3,4,5,6], pattern = [1,1]
OUTPUT
4
EXPLANATION

The pattern [1,1] indicates that we are looking for strictly increasing subarrays of size 3. In the array nums, the subarrays [1,2,3], [2,3,4], [3,4,5], and [4,5,6] match this pattern. Hence, there are 4 subarrays in nums that match the pattern.

Example 2
INPUT
nums = [1,4,4,1,3,5,5,3], pattern = [1,0,-1]
OUTPUT
2
EXPLANATION

Here, the pattern [1,0,-1] indicates that we are looking for a sequence where the first number is smaller than the second, the second is equal to the third, and the third is greater than the fourth. In the array nums, the subarrays [1,4,4,1], and [3,5,5,3] match this pattern. Hence, there are 2 subarrays in nums that match the pattern.

Constraints

2 <= n == nums.length <= 100
1 <= nums[i] <= 109
1 <= m == pattern.length < n
1 <= pattern[i] <= 1

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