How to Solve Number of Ways of Cutting a Pizza Leetcode Problem - Interview Coder Guide
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How to Solve Number of Ways of Cutting a Pizza Problem

Master the Number of Ways of Cutting a Pizza LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.

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Hard#1555
LeetCode Problem

Number of Ways of Cutting a Pizza

Given a rectangular pizza represented as a rows x cols matrix containing the following characters: 'A' (an apple) and '.' (empty cell) and given the integer k. You have to cut the pizza into k pieces ...

ArrayDynamic ProgrammingMemoization+2 more

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Problem Breakdown

Understanding the Number of Ways of Cutting a Pizza Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

Given a rectangular pizza represented as a rows x cols matrix containing the following characters: 'A' (an apple) and '.' (empty cell) and given the integer k. You have to cut the pizza into k pieces using k-1 cuts. For each cut you choose the direction: vertical or horizontal, then you choose a cut position at the cell boundary and cut the pizza into two pieces. If you cut the pizza vertically, give the left part of the pizza to a person. If you cut the pizza horizontally, give the upper part of the pizza to a person. Give the last piece of pizza to the last person. Return the number of ways of cutting the pizza such that each piece contains at least one apple. Since the answer can be a huge number, return this modulo 10^9 + 7.

HardProblem #1555
LeetCode

Number of Ways of Cutting a Pizza

Related Topics
ArrayDynamic ProgrammingMemoizationMatrixPrefix Sum
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Examples

Example 1
INPUT
pizza = ["A..","AAA","..."], k = 3
OUTPUT
3
EXPLANATION

The figure above shows the three ways to cut the pizza. Note that pieces must contain at least one apple.

Example 2
INPUT
pizza = ["A..","AA.","..."], k = 3
OUTPUT
1
Example 3
INPUT
pizza = ["A..","A..","..."], k = 1
OUTPUT
1

Constraints

1 <= rows, cols <= 50
rows == pizza.length
cols == pizza[i].length
1 <= k <= 10
pizza consists of characters 'A' and '.' only.

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