How to Solve Number of Ways Where Square of Number Is Equal to Product of Two Numbers Problem
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Number of Ways Where Square of Number Is Equal to Product of Two Numbers
Given two arrays of integers nums1 and nums2, return the number of triplets formed (type 1 and type 2) under the following rules: Type 1: Triplet (i, j, k) if nums1[i]2 == nums2[j] * nums2[k] where 0 ...
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Understanding the Number of Ways Where Square of Number Is Equal to Product of Two Numbers Problem
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Problem Statement
Given two arrays of integers nums1 and nums2, return the number of triplets formed (type 1 and type 2) under the following rules: Type 1: Triplet (i, j, k) if nums1[i]2 == nums2[j] * nums2[k] where 0 <= i < nums1.length and 0 <= j < k < nums2.length. Type 2: Triplet (i, j, k) if nums2[i]2 == nums1[j] * nums1[k] where 0 <= i < nums2.length and 0 <= j < k < nums1.length.
Number of Ways Where Square of Number Is Equal to Product of Two Numbers
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Examples
nums1 = [7,4], nums2 = [5,2,8,9]1Type 1: (1, 1, 2), nums1[1]2 = nums2[1] * nums2[2]. (42 = 2 * 8).
nums1 = [1,1], nums2 = [1,1,1]9All Triplets are valid, because 12 = 1 * 1. Type 1: (0,0,1), (0,0,2), (0,1,2), (1,0,1), (1,0,2), (1,1,2). nums1[i]2 = nums2[j] * nums2[k]. Type 2: (0,0,1), (1,0,1), (2,0,1). nums2[i]2 = nums1[j] * nums1[k].
nums1 = [7,7,8,3], nums2 = [1,2,9,7]2There are 2 valid triplets. Type 1: (3,0,2). nums1[3]2 = nums2[0] * nums2[2]. Type 2: (3,0,1). nums2[3]2 = nums1[0] * nums1[1].
Constraints
1 <= nums1.length, nums2.length <= 10001 <= nums1[i], nums2[i] <= 105How Interview Coder Helps with Leetcode Problems
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