How to Solve Parsing A Boolean Expression Problem
Master the Parsing A Boolean Expression LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
Interview Coder generates complete solutions and debugging hints that you can use while explaining your approach, so you stay calm and in control.
Parsing A Boolean Expression
A boolean expression is an expression that evaluates to either true or false. It can be in one of the following shapes: 't' that evaluates to true. 'f' that evaluates to false. '!(subExpr)' that evalu...
Interview Coder will help you solve this problem in real-time during your interview
✨ Get instant solutions, explanations, and code generation
Understanding the Parsing A Boolean Expression Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
A boolean expression is an expression that evaluates to either true or false. It can be in one of the following shapes: 't' that evaluates to true. 'f' that evaluates to false. '!(subExpr)' that evaluates to the logical NOT of the inner expression subExpr. '&(subExpr1, subExpr2, ..., subExprn)' that evaluates to the logical AND of the inner expressions subExpr1, subExpr2, ..., subExprn where n >= 1. '|(subExpr1, subExpr2, ..., subExprn)' that evaluates to the logical OR of the inner expressions subExpr1, subExpr2, ..., subExprn where n >= 1. Given a string expression that represents a boolean expression, return the evaluation of that expression. It is guaranteed that the given expression is valid and follows the given rules.
Parsing A Boolean Expression
Related Topics
How Interview Coder Helps
Get real-time assistance for Parsing A Boolean Expression problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
expression = "&(|(f))"falseFirst, evaluate |(f) --> f. The expression is now "&(f)". Then, evaluate &(f) --> f. The expression is now "f". Finally, return false.
expression = "|(f,f,f,t)"trueThe evaluation of (false OR false OR false OR true) is true.
expression = "!(&(f,t))"trueFirst, evaluate &(f,t) --> (false AND true) --> false --> f. The expression is now "!(f)". Then, evaluate !(f) --> NOT false --> true. We return true.
Constraints
1 <= expression.length <= 2 * 104expression[i] is one following characters: '(', ')', '&', '|', '!', 't', 'f', and ','.How Interview Coder Helps with Leetcode Problems
Trust anchors reduce friction for conversion. Reinforce undetectability claims, platform compatibility, user counts, and the free trial to remove perceived risk.
See Interview Coder in Action
Watch how Interview Coder helps solve LeetCode problems during live interviews
Undetectability Checklist
Platform Compatibility
User results and traction
More than 87,000 developers use Interview Coder and early launch metrics showed rapid adoption. Social proof signals that this approach helps real candidates land offers across a range of companies.
Undetectability and technical details
Our native desktop architecture avoids common detection vectors used by browser extensions. We provide a clear checklist so you can run basic checks and confirm the app will be invisible during live interviews.
Platform compatibility and limitations
We work with Zoom, HackerRank, CodeSignal, CoderPad and other web based platforms, with a known list of app version caveats. Check the compatibility note and request a browser link if a specific desktop app is unsupported.
Frequently Asked Questions
Common questions about solving Parsing A Boolean Expression and using Interview Coder during coding interviews.
Interview Coder generates complete solutions instantly with proper complexity analysis, letting you focus on explaining your approach and demonstrating problem-solving skills rather than getting stuck on implementation details during high-pressure situations.
Ready to Get Started?
Download Interview Coder now and join thousands of developers who have aced their coding interviews