How to Solve Power Grid Maintenance Problem
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Power Grid Maintenance
You are given an integer c representing c power stations, each with a unique identifier id from 1 to c (1‑based indexing). These stations are interconnected via n bidirectional cables, represented by ...
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Understanding the Power Grid Maintenance Problem
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Problem Statement
You are given an integer c representing c power stations, each with a unique identifier id from 1 to c (1‑based indexing). These stations are interconnected via n bidirectional cables, represented by a 2D array connections, where each element connections[i] = [ui, vi] indicates a connection between station ui and station vi. Stations that are directly or indirectly connected form a power grid. Initially, all stations are online (operational). You are also given a 2D array queries, where each query is one of the following two types: [1, x]: A maintenance check is requested for station x. If station x is online, it resolves the check by itself. If station x is offline, the check is resolved by the operational station with the smallest id in the same power grid as x. If no operational station exists in that grid, return -1. [2, x]: Station x goes offline (i.e., it becomes non-operational). Return an array of integers representing the results of each query of type [1, x] in the order they appear. Note: The power grid preserves its structure; an offline (non‑operational) node remains part of its grid and taking it offline does not alter connectivity.
Power Grid Maintenance
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Examples
c = 5, connections = [[1,2],[2,3],[3,4],[4,5]], queries = [[1,3],[2,1],[1,1],[2,2],[1,2]]
[3,2,3]
Initially, all stations {1, 2, 3, 4, 5} are online and form a single power grid. Query [1,3]: Station 3 is online, so the maintenance check is resolved by station 3. Query [2,1]: Station 1 goes offline. The remaining online stations are {2, 3, 4, 5}. Query [1,1]: Station 1 is offline, so the check is resolved by the operational station with the smallest id among {2, 3, 4, 5}, which is station 2. Query [2,2]: Station 2 goes offline. The remaining online stations are {3, 4, 5}. Query [1,2]: Station 2 is offline, so the check is resolved by the operational station with the smallest id among {3, 4, 5}, which is station 3.
c = 3, connections = [], queries = [[1,1],[2,1],[1,1]]
Example output
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