How to Solve Promise Time Limit Problem
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Promise Time Limit
Given an asynchronous function fn and a time t in milliseconds, return a new time limited version of the input function. fn takes arguments provided to the time limited function. The time limited func...
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Understanding the Promise Time Limit Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
Given an asynchronous function fn and a time t in milliseconds, return a new time limited version of the input function. fn takes arguments provided to the time limited function. The time limited function should follow these rules: If the fn completes within the time limit of t milliseconds, the time limited function should resolve with the result. If the execution of the fn exceeds the time limit, the time limited function should reject with the string "Time Limit Exceeded".
Promise Time Limit
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Examples
Example input{"rejected":"Time Limit Exceeded","time":50}const limited = timeLimit(fn, t) const start = performance.now() let result; try { const res = await limited(...inputs) result = {"resolved": res, "time": Math.floor(performance.now() - start)}; } catch (err) { result = {"rejected": err, "time": Math.floor(performance.now() - start)}; } console.log(result) // Output The provided function is set to resolve after 100ms. However, the time limit is set to 50ms. It rejects at t=50ms because the time limit was reached.
Example input{"resolved":25,"time":100}The function resolved 5 * 5 = 25 at t=100ms. The time limit is never reached.
Example input{"resolved":15,"time":120}The function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.
Example input{"rejected":"Error","time":0}The function immediately throws an error.
Constraints
0 <= inputs.length <= 100 <= t <= 1000fn returns a promiseHow Interview Coder Helps with Leetcode Problems
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