How to Solve Remove Outermost Parentheses Leetcode Problem - Interview Coder Guide
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How to Solve Remove Outermost Parentheses Problem

Master the Remove Outermost Parentheses LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.

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Easy#1078
LeetCode Problem

Remove Outermost Parentheses

A valid parentheses string is either empty "", "(" + A + ")", or A + B, where A and B are valid parentheses strings, and + represents string concatenation. For example, "", "()", "(())()", and "(()(()...

StringStack

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Problem Breakdown

Understanding the Remove Outermost Parentheses Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

A valid parentheses string is either empty "", "(" + A + ")", or A + B, where A and B are valid parentheses strings, and + represents string concatenation. For example, "", "()", "(())()", and "(()(()))" are all valid parentheses strings. A valid parentheses string s is primitive if it is nonempty, and there does not exist a way to split it into s = A + B, with A and B nonempty valid parentheses strings. Given a valid parentheses string s, consider its primitive decomposition: s = P1 + P2 + ... + Pk, where Pi are primitive valid parentheses strings. Return s after removing the outermost parentheses of every primitive string in the primitive decomposition of s.

EasyProblem #1078
LeetCode

Remove Outermost Parentheses

Related Topics
StringStack
How Interview Coder Helps

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Examples

Example 1
INPUT
s = "(()())(())"
OUTPUT
"()()()"
EXPLANATION

The input string is "(()())(())", with primitive decomposition "(()())" + "(())". After removing outer parentheses of each part, this is "()()" + "()" = "()()()".

Example 2
INPUT
s = "(()())(())(()(()))"
OUTPUT
"()()()()(())"
EXPLANATION

The input string is "(()())(())(()(()))", with primitive decomposition "(()())" + "(())" + "(()(()))". After removing outer parentheses of each part, this is "()()" + "()" + "()(())" = "()()()()(())".

Example 3
INPUT
s = "()()"
OUTPUT
""
EXPLANATION

The input string is "()()", with primitive decomposition "()" + "()". After removing outer parentheses of each part, this is "" + "" = "".

Constraints

1 <= s.length <= 105
s[i] is either '(' or ')'.
s is a valid parentheses string.

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