How to Solve Removing Minimum Number of Magic Beans Leetcode Problem - Interview Coder Guide
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How to Solve Removing Minimum Number of Magic Beans Problem

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Medium#2290
LeetCode Problem

Removing Minimum Number of Magic Beans

You are given an array of positive integers beans, where each integer represents the number of magic beans found in a particular magic bag. Remove any number of beans (possibly none) from each bag suc...

ArrayGreedySorting+2 more

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Problem Breakdown

Understanding the Removing Minimum Number of Magic Beans Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given an array of positive integers beans, where each integer represents the number of magic beans found in a particular magic bag. Remove any number of beans (possibly none) from each bag such that the number of beans in each remaining non-empty bag (still containing at least one bean) is equal. Once a bean has been removed from a bag, you are not allowed to return it to any of the bags. Return the minimum number of magic beans that you have to remove.

MediumProblem #2290
LeetCode

Removing Minimum Number of Magic Beans

Related Topics
ArrayGreedySortingEnumerationPrefix Sum
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Examples

Example 1
INPUT
beans = [4,1,6,5]
OUTPUT
4
EXPLANATION

- We remove 1 bean from the bag with only 1 bean. This results in the remaining bags: [4,0,6,5] - Then we remove 2 beans from the bag with 6 beans. This results in the remaining bags: [4,0,4,5] - Then we remove 1 bean from the bag with 5 beans. This results in the remaining bags: [4,0,4,4] We removed a total of 1 + 2 + 1 = 4 beans to make the remaining non-empty bags have an equal number of beans. There are no other solutions that remove 4 beans or fewer.

Example 2
INPUT
beans = [2,10,3,2]
OUTPUT
7
EXPLANATION

- We remove 2 beans from one of the bags with 2 beans. This results in the remaining bags: [0,10,3,2] - Then we remove 2 beans from the other bag with 2 beans. This results in the remaining bags: [0,10,3,0] - Then we remove 3 beans from the bag with 3 beans. This results in the remaining bags: [0,10,0,0] We removed a total of 2 + 2 + 3 = 7 beans to make the remaining non-empty bags have an equal number of beans. There are no other solutions that removes 7 beans or fewer.

Constraints

1 <= beans.length <= 105
1 <= beans[i] <= 105

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