How to Solve Scramble String Leetcode Problem - Interview Coder Guide
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How to Solve Scramble String Problem

Master the Scramble String LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.

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Hard#87
LeetCode Problem

Scramble String

We can scramble a string s to get a string t using the following algorithm: If the length of the string is 1, stop. If the length of the string is > 1, do the following: Split the string into two non-...

StringDynamic Programming

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Problem Breakdown

Understanding the Scramble String Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

We can scramble a string s to get a string t using the following algorithm: If the length of the string is 1, stop. If the length of the string is > 1, do the following: Split the string into two non-empty substrings at a random index, i.e., if the string is s, divide it to x and y where s = x + y. Randomly decide to swap the two substrings or to keep them in the same order. i.e., after this step, s may become s = x + y or s = y + x. Apply step 1 recursively on each of the two substrings x and y. Given two strings s1 and s2 of the same length, return true if s2 is a scrambled string of s1, otherwise, return false.

HardProblem #87
LeetCode

Scramble String

Related Topics
StringDynamic Programming
How Interview Coder Helps

Get real-time assistance for Scramble String problems during coding interviews. Interview Coder provides instant solutions and explanations.

Examples

Example 1
INPUT
s1 = "great", s2 = "rgeat"
OUTPUT
true
EXPLANATION

One possible scenario applied on s1 is: "great" --> "gr/eat" // divide at random index. "gr/eat" --> "gr/eat" // random decision is not to swap the two substrings and keep them in order. "gr/eat" --> "g/r / e/at" // apply the same algorithm recursively on both substrings. divide at random index each of them. "g/r / e/at" --> "r/g / e/at" // random decision was to swap the first substring and to keep the second substring in the same order. "r/g / e/at" --> "r/g / e/ a/t" // again apply the algorithm recursively, divide "at" to "a/t". "r/g / e/ a/t" --> "r/g / e/ a/t" // random decision is to keep both substrings in the same order. The algorithm stops now, and the result string is "rgeat" which is s2. As one possible scenario led s1 to be scrambled to s2, we return true.

Example 2
INPUT
s1 = "abcde", s2 = "caebd"
OUTPUT
false
Example 3
INPUT
s1 = "a", s2 = "a"
OUTPUT
true

Constraints

s1.length == s2.length
1 <= s1.length <= 30
s1 and s2 consist of lowercase English letters.

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Frequently Asked Questions

Common questions about solving Scramble String and using Interview Coder during coding interviews.

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