How to Solve Sum of Total Strength of Wizards Leetcode Problem - Interview Coder Guide
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How to Solve Sum of Total Strength of Wizards Problem

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Hard#2368
LeetCode Problem

Sum of Total Strength of Wizards

As the ruler of a kingdom, you have an army of wizards at your command. You are given a 0-indexed integer array strength, where strength[i] denotes the strength of the ith wizard. For a contiguous gro...

ArrayStackMonotonic Stack+1 more

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Problem Breakdown

Understanding the Sum of Total Strength of Wizards Problem

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Problem Statement

As the ruler of a kingdom, you have an army of wizards at your command. You are given a 0-indexed integer array strength, where strength[i] denotes the strength of the ith wizard. For a contiguous group of wizards (i.e. the wizards' strengths form a subarray of strength), the total strength is defined as the product of the following two values: The strength of the weakest wizard in the group. The total of all the individual strengths of the wizards in the group. Return the sum of the total strengths of all contiguous groups of wizards. Since the answer may be very large, return it modulo 109 + 7. A subarray is a contiguous non-empty sequence of elements within an array.

HardProblem #2368
LeetCode

Sum of Total Strength of Wizards

Related Topics
ArrayStackMonotonic StackPrefix Sum
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Examples

Example 1
INPUT
strength = [1,3,1,2]
OUTPUT
44
EXPLANATION

The following are all the contiguous groups of wizards: - [1] from [1,3,1,2] has a total strength of min([1]) * sum([1]) = 1 * 1 = 1 - [3] from [1,3,1,2] has a total strength of min([3]) * sum([3]) = 3 * 3 = 9 - [1] from [1,3,1,2] has a total strength of min([1]) * sum([1]) = 1 * 1 = 1 - [2] from [1,3,1,2] has a total strength of min([2]) * sum([2]) = 2 * 2 = 4 - [1,3] from [1,3,1,2] has a total strength of min([1,3]) * sum([1,3]) = 1 * 4 = 4 - [3,1] from [1,3,1,2] has a total strength of min([3,1]) * sum([3,1]) = 1 * 4 = 4 - [1,2] from [1,3,1,2] has a total strength of min([1,2]) * sum([1,2]) = 1 * 3 = 3 - [1,3,1] from [1,3,1,2] has a total strength of min([1,3,1]) * sum([1,3,1]) = 1 * 5 = 5 - [3,1,2] from [1,3,1,2] has a total strength of min([3,1,2]) * sum([3,1,2]) = 1 * 6 = 6 - [1,3,1,2] from [1,3,1,2] has a total strength of min([1,3,1,2]) * sum([1,3,1,2]) = 1 * 7 = 7 The sum of all the total strengths is 1 + 9 + 1 + 4 + 4 + 4 + 3 + 5 + 6 + 7 = 44.

Example 2
INPUT
strength = [5,4,6]
OUTPUT
213
EXPLANATION

The following are all the contiguous groups of wizards: - [5] from [5,4,6] has a total strength of min([5]) * sum([5]) = 5 * 5 = 25 - [4] from [5,4,6] has a total strength of min([4]) * sum([4]) = 4 * 4 = 16 - [6] from [5,4,6] h

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