How to Solve Two Best Non- Overlapping Events Leetcode Problem - Interview Coder Guide
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How to Solve Two Best Non- Overlapping Events Problem

Master the Two Best Non- Overlapping Events LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.

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Medium#2164
LeetCode Problem

Two Best Non-Overlapping Events

You are given a 0-indexed 2D integer array of events where events[i] = [startTimei, endTimei, valuei]. The ith event starts at startTimei and ends at endTimei, and if you attend this event, you will r...

ArrayBinary SearchDynamic Programming+2 more

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Problem Breakdown

Understanding the Two Best Non- Overlapping Events Problem

Let's break down this LeetCode problem and understand what makes it challenging in interview settings.

Problem Statement

You are given a 0-indexed 2D integer array of events where events[i] = [startTimei, endTimei, valuei]. The ith event starts at startTimei and ends at endTimei, and if you attend this event, you will receive a value of valuei. You can choose at most two non-overlapping events to attend such that the sum of their values is maximized. Return this maximum sum. Note that the start time and end time is inclusive: that is, you cannot attend two events where one of them starts and the other ends at the same time. More specifically, if you attend an event with end time t, the next event must start at or after t + 1.

MediumProblem #2164
LeetCode

Two Best Non-Overlapping Events

Related Topics
ArrayBinary SearchDynamic ProgrammingSortingHeap (Priority Queue)
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Get real-time assistance for Two Best Non-Overlapping Events problems during coding interviews. Interview Coder provides instant solutions and explanations.

Examples

Example 1
INPUT
events = [[1,3,2],[4,5,2],[2,4,3]]
OUTPUT
4
EXPLANATION

Choose the green events, 0 and 1 for a sum of 2 + 2 = 4.

Example 2
INPUT
events = [[1,3,2],[4,5,2],[1,5,5]]
OUTPUT
5
EXPLANATION

Choose event 2 for a sum of 5.

Example 3
INPUT
events = [[1,5,3],[1,5,1],[6,6,5]]
OUTPUT
8
EXPLANATION

Choose events 0 and 2 for a sum of 3 + 5 = 8.

Constraints

2 <= events.length <= 105
events[i].length == 3
1 <= startTimei <= endTimei <= 109
1 <= valuei <= 106

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