How to Solve Word Ladder Problem
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Word Ladder
A transformation sequence from word beginWord to word endWord using a dictionary wordList is a sequence of words beginWord -> s1 -> s2 -> ... -> sk such that: Every adjacent pair of words differs by a...
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Understanding the Word Ladder Problem
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Problem Statement
A transformation sequence from word beginWord to word endWord using a dictionary wordList is a sequence of words beginWord -> s1 -> s2 -> ... -> sk such that: Every adjacent pair of words differs by a single letter. Every si for 1 <= i <= k is in wordList. Note that beginWord does not need to be in wordList. sk == endWord Given two words, beginWord and endWord, and a dictionary wordList, return the number of words in the shortest transformation sequence from beginWord to endWord, or 0 if no such sequence exists.
Word Ladder
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Examples
beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log","cog"]5One shortest transformation sequence is "hit" -> "hot" -> "dot" -> "dog" -> cog", which is 5 words long.
beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log"]0The endWord "cog" is not in wordList, therefore there is no valid transformation sequence.
Constraints
1 <= beginWord.length <= 10endWord.length == beginWord.length1 <= wordList.length <= 5000wordList[i].length == beginWord.lengthbeginWord, endWord, and wordList[i] consist of lowercase English letters.beginWord != endWordAll the words in wordList are unique.How Interview Coder Helps with Leetcode Problems
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