How to Solve Words Within Two Edits of Dictionary Problem
Master the Words Within Two Edits of Dictionary LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
Interview Coder generates complete solutions and debugging hints that you can use while explaining your approach, so you stay calm and in control.
Words Within Two Edits of Dictionary
You are given two string arrays, queries and dictionary. All words in each array comprise of lowercase English letters and have the same length. In one edit you can take a word from queries, and chang...
Interview Coder will help you solve this problem in real-time during your interview
✨ Get instant solutions, explanations, and code generation
Understanding the Words Within Two Edits of Dictionary Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given two string arrays, queries and dictionary. All words in each array comprise of lowercase English letters and have the same length. In one edit you can take a word from queries, and change any letter in it to any other letter. Find all words from queries that, after a maximum of two edits, equal some word from dictionary. Return a list of all words from queries, that match with some word from dictionary after a maximum of two edits. Return the words in the same order they appear in queries.
Words Within Two Edits of Dictionary
Related Topics
How Interview Coder Helps
Get real-time assistance for Words Within Two Edits of Dictionary problems during coding interviews. Interview Coder provides instant solutions and explanations.
Examples
queries = ["word","note","ants","wood"], dictionary = ["wood","joke","moat"]
["word","note","wood"]
- Changing the 'r' in "word" to 'o' allows it to equal the dictionary word "wood". - Changing the 'n' to 'j' and the 't' to 'k' in "note" changes it to "joke". - It would take more than 2 edits for "ants" to equal a dictionary word. - "wood" can remain unchanged (0 edits) and match the corresponding dictionary word. Thus, we return ["word","note","wood"].
queries = ["yes"], dictionary = ["not"]
[]
Applying any two edits to "yes" cannot make it equal to "not". Thus, we return an empty array.
Constraints
1 <= queries.length, dictionary.length <= 100
n == queries[i].length == dictionary[j].length
1 <= n <= 100
All queries[i] and dictionary[j] are composed of lowercase English letters.
How Interview Coder Helps with Leetcode Problems
Trust anchors reduce friction for conversion. Reinforce undetectability claims, platform compatibility, user counts, and the free trial to remove perceived risk.
See Interview Coder in Action
Watch how Interview Coder helps solve LeetCode problems during live interviews
Undetectability Checklist
Platform Compatibility
User results and traction
More than 87,000 developers use Interview Coder and early launch metrics showed rapid adoption. Social proof signals that this approach helps real candidates land offers across a range of companies.
Undetectability and technical details
Our native desktop architecture avoids common detection vectors used by browser extensions. We provide a clear checklist so you can run basic checks and confirm the app will be invisible during live interviews.
Platform compatibility and limitations
We work with Zoom, HackerRank, CodeSignal, CoderPad and other web based platforms, with a known list of app version caveats. Check the compatibility note and request a browser link if a specific desktop app is unsupported.
Frequently Asked Questions
Common questions about solving Words Within Two Edits of Dictionary and using Interview Coder during coding interviews.
Interview Coder generates complete solutions instantly with proper complexity analysis, letting you focus on explaining your approach and demonstrating problem-solving skills rather than getting stuck on implementation details during high-pressure situations.
Ready to Get Started?
Download Interview Coder now and join thousands of developers who have aced their coding interviews